X^2/(0.53-X)=10^-3.8

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Solution for X^2/(0.53-X)=10^-3.8 equation: 


D( X )

0.53-X = 0

0.53-X = 0

0.53-X = 0

0.53-X = 0 // - 0.53

-X = -0.53 // * -1

X = 0.53

X in (-oo:0.53) U (0.53:+oo)

(X^2)/(0.53-X) = 10^-3.8 // - 10^-3.8

(X^2)/(0.53-X)-10^-3.8 = 0

(X^2)/(0.53-X)+(-10^-3.8*(0.53-X))/(0.53-X) = 0

X^2-10^-3.8*(0.53-X) = 0

X^2+10^-3.8*X+0.53*(-10^-3.8) = 0

X^2+10^-3.8*X+0.53*(-10^-3.8) = 0

X^2+10^-3.8*X+0.53*(-10^-3.8) = 0

DELTA = (10^-3.8)^2-(0.53*1*4*(-10^-3.8))

DELTA = 10^-7.6-2.12*10^-3.8

DELTA = -0.0003359688

DELTA < 0

1 = 0

1/(0.53-X) = 0

1/(0.53-X) = 0 // * 0.53-X

1 = 0

X belongs to the empty set

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